- Paint Code For Sketch 1 0 10
- Paint Code For Sketch 1 0 1 0 1 Sequence
- Paint Code For Sketch 1 0 1 Fertilizer
- Paint Code For Sketch 1 0 1 Beta
PaintCode is a unique vector drawing app that generates Objective-C or Swift code in real time, acting as a bridge between developers and graphic designers. PaintCode - Turn your drawings into Objective-C or Swift drawing code. PaintCode produces methods that use android.graphics API to draw 2D graphics on provided canvas (android.graphics.Canvas). So for example for this House Icon drawing: following code will be generated: void drawHouseIcon(Canvas canvas) // General Declarations Paint paint; // Local Colors int houseIconColor = Color.argb(255, 0, 149, 233); // Bezier RectF bezierRect = new RectF(2f, 1. Photo to Color Sketch 2.95: 1.9 MB: Shareware: $27.5: It's easy to make sketch from photo.Convert your photo (jpg or bmp format) into color sketch, pen-and-ink, black and white sketch.Now, your photo become fine line art, even indistinguishable from an artist work.
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Composition of Functions:
Composing with Sets of Points (page 1 of 6)
Composing with Sets of Points (page 1 of 6)
View paint code.docx from MATH 102 at Islamia University of Bahawalpur. Main struct click choice; int i,j,fn,x1,y1,x2,y2,x3,y3,type,menuch; char font25,k; /int. Quickly import design assets from Sketch. Our plugin allows you to easily copy artboards out of Sketch and bring layers into Axure RP as individual widgets. Once in Axure, all of your Sketch assets will be editable and ready for building interactions. Need more information? Check out our blog post on the Sketch plugin. Download the Sketch Plugin.
Sections: Composing functions that are sets of point, Composing functions at points, Composing functions with other functions, Word problems using composition, Inverse functions and composition
Until now, given a function f(x), you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given f(x) = 2x + 3, you could find f(y2 – 1) by plugging y2 – 1 in for x to get f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1.
In function composition, you're plugging entire functions in for the x. In other words, you're always getting 'fancy'. But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of (x, y) points:
- Let f = {(–2, 3), (–1, 1), (0, 0), (1, –1), (2, –3)} and
let g = {(–3, 1), (–1, –2), (0, 2), (2, 2), (3, 1)}.
Find (i)f (1), (ii) g(–1), and (iii) (gof )(1).
(i) This type of exercise is meant to emphasize that the (x, y) points are really (x, f (x)) points. To find f (1), I need to find the (x, y) point in the set of (x, f (x)) points that has a first coordinate of x = 1. Then f (1) is the y-value of that point. In this case, the point with x = 1 is (1, –1), so:
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f (1) = –1
(ii) The point in the g(x) set of point with x = –1 is the point (–1, –2), so:
g(–1) = –2
(iii) What is '(gof )(1)'? This is read as 'g-compose-f of 1', and means 'plug 1 into f, evaluate, and then plug the result into g'. The computation can feel a lot easier if I use the following, more intuitive, formatting:
(gof )(1) = g( f(1))
Now I'll work in steps, keeping in mind that, while I may be used to doing things from the left to the right (because that's how we read), composition works from the right to the left (or, if you prefer, from the inside out). So I'll start with the x = 1. I am plugging this into f(x), so I look in the set of f(x) points for a point with x = 1. The point is (1, –1). This tells me that f(1) = –1, so now I have: Copyright © Elizabeth Stapel 2002-2011 All Rights Reserved
(gof )(1) = g( f(1)) = g(–1)
Working from the right back toward the left, I am now plugging x = –1 (from 'f(1) = –1') into g(x), so I look in the set of g(x) points for a point with x = –1. That point is (–1, –2). This tells me that g(–1) = –2, so now I have my answer:
(gof )(1) = g( f(1)) = g(–1) = –2
Note that they never told us what were the formulas, if any, for f(x) or g(x); we were only given a list of points. But this list was sufficient for answering the question, as long as we keep track of our x- and y-values.
![Paintcode For Sketch 1 0 1 Paintcode For Sketch 1 0 1](https://www.paintcodeapp.com/content/news/2016-03-29_how-to-use-paintcode-plugin-for-sketch/sheet_2x.png)
![Sketch Sketch](https://i.ytimg.com/vi/tZVrc8Y67AI/maxresdefault.jpg)
- Let f = {(–2, 3), (–1, 1), (0, 0), (1, –1), (2, –3)} and
let g = {(–3, 1), (–1, –2), (0, 2), (2, 2), (3, 1)}.
Find (i) ( fog)(0), (ii)( fog)(–1), and (iii)(gof )(–1).
(i) To find ( fog)(0), ('f-compose-g of zero'), I'll rewrite the expression as:
( fog)(0) = f(g(0))
This tells me that I'm going to plug zero into g(x), simplify, and then plug the result into f(x). Looking at the list of g(x) points, I find (0, 2), so g(0) = 2, and I need now to find f(2). Looking at the list of f(x) points, I find (2, –3), so f(2) = –3. Then:
( fog)(0) = f(g(0)) = f(2) = –3
(ii) The second part works the same way:
( fog)(–1) = f(g(–1)) = f(–2) = 3
(iii) I can rewrite the composition as (gof )(–1) = g( f(–1)) = g(1).
Uh-oh; there is no g(x) point with x = 1, so it is nonsense to try to find the value of g(1). In math-speak, g(1) is 'not defined'; that is, it is nonsense.Then (gof )(–1) is also nonsense, so the answer is:
(gof )(–1) is undefined.
Part (iii) of the above example points out an important consideration regarding domains and ranges. It may be that your composed function (the result you get after composing two other functions) will have a restricted domain, or at least a domain that is more restricted than you might otherwise have expected. This will be more important when we deal with composing functions symbolically later.
Another exercise of this type gives you two graphs, rather than two sets of points, and has you read the points (the function values) from these graphs.
- Given f(x) and g(x) as shown below, find ( fog)(–1).
In this case, I will read the points from the graph. I've been asked to find ( fog)(–1) = f(g(–1)). This means that I first need to find g(–1). So I look on the graph of g(x), and find x = –1. Tracing up from x = –1 to the graph of g(x), I arrive at y = 3. Then the point (–1, 3) is on the graph of g(x), and g(–1) = 3.
Now I plug this value, x = 3, into f(x). To do this, I look at the graph of f(x) and find x = 3. Tracing up from x = 3 to the graph of f(x), I arrive at y = 3. Then the point (3, 3) is on the graph of f(x), and f(3) = 3.
Then( fog)(–1) = f(g(–1)) = f(3) = 3.
- Given f(x) and g(x) as shown in the graphs below, find (gof )(x) for integral values of x on the interval –3 <x< 3.
f(x): | g(x): |
This is asking me for all the values of (gof )(x) = g( f(x)) for x = –3, –2, –1, 0, 1, 2, and 3. So I'll just follow the points on the graphs and compute all the values:
(gof )(–3) = g( f(–3)) = g(1) = –1
I got this answer by looking at x = –3 on the f(x) graph, finding the corresponding y-value of 1 on the f(x) graph, and using this answer as my new x-value on the g(x) graph. That is, I looked at x = –3 on the f(x) graph, found that this led to y = 1, went to x = 1 on the g(x) graph, and found that this led to y = –1. Similarly:
(gof )(–2) = g( f(–2)) = g(–1) = 3
(gof )(–1) = g( f(–1)) = g(–3) = –2
(gof )(0) = g( f(0)) = g(–2) = 0
(gof )(1) = g( f(1)) = g(0) = 2
(gof )(2) = g( f(2)) = g(2) = –3
(gof )(3) = g( f(3)) = g(3) = 1
(gof )(–1) = g( f(–1)) = g(–3) = –2
(gof )(0) = g( f(0)) = g(–2) = 0
(gof )(1) = g( f(1)) = g(0) = 2
(gof )(2) = g( f(2)) = g(2) = –3
(gof )(3) = g( f(3)) = g(3) = 1
You aren't generally given functions as sets of points or as graphs, however. Generally, you have formulas for your functions. So let's see what composition looks like in that case...
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Cite this article as: | Stapel, Elizabeth. 'Composing with Sets of Points.' Purplemath. Available from https://www.purplemath.com/modules/fcncomp.htm. Accessed [Date] [Month] 2016 |
Paint Code For Sketch 1 0 10
I’ve been using PaintCode since it first became available, and really think it’s a brilliant app. PaintCode lets you draw vector graphics and it outputs Objective-C code that you can use in your own apps. One of the initial questions I had was, “Where do I put this code that I got from PaintCode?” The documentation focuses on using the drawing features of the app itself, and there isn’t much on the Web yet describing how to use the code.
As an iOS beginner, I’ve found drawing to be very confusing. Quartz, Core Graphics, Core Animation and UIKit are terms of frameworks used for drawing in iOS, and when to use each isn’t very clear. There is also a fair bit of overlap among these, and the addition of ARC adds more worry. UIView, UILabel, CALayer, and CAShapeLayer are all places where you might want drawing, and, falling into the bad habit of view controller bloat, I tended to try drawing in my UIViewControllers as well. PaintCode let me easily create just the shape I wanted, and I had the relevant Objective-C code in-hand, but I didn’t know what to do with it.
Paint Code For Sketch 1 0 1 0 1 Sequence
An easy way to streamline the multitude of choices is to realize that PaintCode outputs UIKit code. UIKit is the newer, friendlier Objective-C wrapper around much of Core Graphics, which is an older C framework. UIView is the vanilla class for placing things on-screen in UIKit. Voila! Stick the PaintCode code in a UIView, and all the worries go away. Where in the UIView, you might ask? In DrawRect:.
As an example, I updated the shape of Snoozy’s tint picker reticle for an upcoming release. The original, drawn as a pair of nested circles in my view controller, had the problem of being covered up by the user’s finger while being moved. I wanted to add a handle below the loop to resolve this issue.
The old tint reticle on the left, the new on the right.
PaintCode allowed me to quickly draw the shape I wanted, and to get the Objective-C code to do the drawing. I could have drawn the shape in PhotoShop, output an image file and then used UIImage to get the reticle on-screen, and this might even have certain advantages, but part of my motivation when creating features is to learn, and learning how to draw in iOS is something I want to get better at.
I subclassed UIView to create a TintPickerReticleView. Here is the entire .m:
Everything inside the DrawRect: method was output from PaintCode.
Inside my view controller, I declare a property with this new type:
Inside my view controller, I declare a property with this new type:
And then create a tintReticle with this method:
Paint Code For Sketch 1 0 1 Fertilizer
And call the creation method when needed. Be sure to add your new view instance as a subview in your view hierarchy (I do this by setting the layer) and call setNeedsDisplay. These are two big reasons why drawRect isn’t called. Another is forgetting to set the frame.
Paint Code For Sketch 1 0 1 Beta
Much of the documentation provided by software vendors, the Q&A on Stack Overflow and other developer forums, and online tutorials start with an assumption that the new developer already has a baseline of knowledge that, despite much effort on my part, I just don’t always have. A simple question like, “Where do I place this drawing code?” can feel like an embarrassing question to ask. Hopefully this post helps someone else who found themselves asking the same.